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File: 1788431234150612.png πŸ“₯︎ (114.77 KB, 680x632) ImgOps

 β„–17590152[Quote]

Are you smart enough to earn 650k nusoi?

 β„–17590187[Quote]

3%

 β„–17590693[Quote]

13/27?

 β„–17590715[Quote]

50% since one is already guaranteed to be a boy

 β„–17590723[Quote]

>>17590693
YOOOO I GOT IT RIGHT
I'm gifted and autistic so it checks out

 β„–17590743[Quote]

>>17590715
it's 66% you're stupid

 β„–17590767[Quote]

>>17590152 (OP)
This is some trick question bullshit isn't it

 β„–17590799[Quote]

>>17590693
This teen is right
Consider all the possibilities
Boy tuesday, girl monday
Boy tuesday, girl tuesday

Boy tuesday, boy monday
Boy tuesday, boy tuesday

Now keep in mind that every option EXCEPT boy tuesday, boy tuesday has 2 potential orders so they're twice as likely
14 possibilities, 1 of which is half as likely, means the denominator is 13.5
The options for a boy to be picked as the second child is 6.5 (not 7 since boy Tuesday, boy Tuesday) is half as likely
Final answer is 6.5/13.5 = 13/27

 β„–17590810[Quote]

>>17590799
aspGODs won

 β„–17590898[Quote]

Here's another interview question:
compute E[X>0|X+Y>0] for X,Y iid N(0,1)
can a more educated 'dult help me out? I don't know much about this notation so I assume the answer is 1 (too trivial though)

 β„–17590916[Quote]

An easier one; this is something you can do if you know any statistics
>You test 100 trading signals. 5 reject the null at p < 0.05. Are any real?

 β„–17590918[Quote]

every game theorist i've met acts like Dilbert it's so fucking weird

 β„–17590954[Quote]

>>17590898
X,Y iid N(0,1) means X and Y are independent normal variables with mean 0 and variance 1
This one is harder

>>17590916
Probably not, but it depends on the exact p values, if 4 of them have p=0.04 or some bs and one has p=0.00001 there's a high chance the 5th one is real

 β„–17591031[Quote]

>>17590898
Wait is this E[X|X+Y>0] or P(X>0|X+Y>0)? The notation given doesn't make much sense

 β„–17591107[Quote]

>>17591031
I don't fucking know bro



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