β16158750[Quote]
x = Οͺ
β16158764[Quote]
Ο β((β5 - 1)/2) (or equivalently Ο / βΟ, where Ο = (1 + β5)/2 is the golden ratio).
This matches the numerical value β 2.469767 (computed via quadrature).
Quick derivation outline (Feynman's trick or other methods)
One way to derive it is to consider the parameterized integral
I(a) = β«β^β arctan(a / (xΒ² + 1)) dx,
differentiate under the integral sign to get a rational integrand in x, integrate that (via factoring the resulting quartic denominator into quadratics involving β(1 + aΒ²)), and solve the resulting ODE for I(a) with I(0) = 0. At a = 2 it yields the golden-ratio form.
Alternative approaches (as seen in sources) include integration by parts, trigonometric substitution (x = tan ΞΈ), or contour integration in the complex plane. The connection to Ο arises naturally from the quadratic roots when evaluating the antiderivative or definite limits.
The integral converges nicely (the integrand behaves like arctan(2/xΒ²) ~ 2/xΒ² at infinity and is bounded near 0).
β16158778[Quote]
porbably pi or something like that
β16158785[Quote]
use AI maybe
β16158790[Quote]
>>16158764That's correct… nusois have become too good
β16158817[Quote]
>>16158790meds he vibemathed it
β16158966[Quote]
I HATE integrals, so no.
β16158972[Quote]
I canβt do differential equations yet, post again in 5 months
β16159001[Quote]
i plan to learn integral calculus by reading a textbook please ask this again in a year
β16159006[Quote]
>>16158966we :transheart: integrals here xister
>>16158972same